In the circuit diagram given below, the current flowing across 5 ohm resistor is 1 amp. Find the current flowing through the other two resistors.
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Given:
1 amp current is flowing through 5ohm resistor.
We know that in case of parallel connection, the p.d. across each resistor is same and is equal to the voltage applied.
Therefore, applied voltage, V = IR = 1 × 5 = 5V
So,
Current through 4 ohm resistor = $\frac{\text{V}}{\text{R}}=\frac{5}{4}=1.25\text{A}$
Current through 10 ohm resistor = $\frac{\text{V}}{\text{R}}=\frac{5}{10}=0.5\text{A}$
1 amp current is flowing through 5ohm resistor.
We know that in case of parallel connection, the p.d. across each resistor is same and is equal to the voltage applied.
Therefore, applied voltage, V = IR = 1 × 5 = 5V
So,
Current through 4 ohm resistor = $\frac{\text{V}}{\text{R}}=\frac{5}{4}=1.25\text{A}$
Current through 10 ohm resistor = $\frac{\text{V}}{\text{R}}=\frac{5}{10}=0.5\text{A}$
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