MCQ
In the combustion of $2.0\,gm$ of methane $25\,kcal$ heat is liberated, heat of combustion of methane would be.....$kcal$
  • A
    $100$
  • $200$
  • C
    $300$
  • D
    $400$

Answer

Correct option: B.
$200$
(b)$C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O$
Molecular weight of $C{H_4} = 12 + 4 = 16$
$\therefore $ On the combustion of $ 2.0$ $gm$ of methane $= 25.0 \,kcal$
$\therefore $ On the combustion of $16.0\,gm = \frac{{25 \times 16}}{2} = 200\,kcal.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free