MCQ
In the circuit below, $A$ and $B$ represent two inputs and $C$ represents the output.
- ✓$OR $ gate
- B$NOR$ gate
- C$AND $ gate
- D$NAND$ gate
✓
Answer
Correct option: A.
$OR $ gate
a
$\begin{array}{|c|c|c|}\hline A & {B} & {C} \\ \hline 1 & {1} & {1} \\ \hline 1 & {0} & {1} \\ \hline 0 & {1} & {1} \\ \hline 0 & {0} & {0} \\ \hline\end{array}$
$\begin{array}{|c|c|c|}\hline A & {B} & {C} \\ \hline 1 & {1} & {1} \\ \hline 1 & {0} & {1} \\ \hline 0 & {1} & {1} \\ \hline 0 & {0} & {0} \\ \hline\end{array}$
The truth table for the above logic gate is:
This truth table follows the boolean algebra $C=A+B$ which is for $OR$ gate
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