MCQ
In the circuit shown, if a conducting wire is connected between points $A$ and $B,$ the current in this wire will
  • A
    flow from $A$ to $B $ 
  • flow from $B $ to $A$
  • C
    flow in the direction which will be decided by the vaule of $V$ 
  • D
    be zero

Answer

Correct option: B.
flow from $B $ to $A$
b
Current through arm $C A D$,   $I=\frac{V}{8}\, amp$

Potential difference between $C$ and $A=V_{C}-V_{A}$

$=\frac{V}{8} \times 4=\frac{V}{2}\, \mathrm{volt}$

Current through $C B D$,   $I^{\prime}=\frac{V}{4}\, amp$

Potential difference between $C$ and $B=V_{C}-V_{B}$

$=\frac{V}{4} \times 1=\frac{V}{4} \,\text { volt. }$

Potential between $A$ and $B=V_{A}-V_{B}$

$\therefore \quad V_{A}-V_{B}=V_{C}-V_{B}-\left(V_{C}-V_{A}\right)=\frac{V}{4}-\frac{V}{2}=\frac{V}{4}$

$ \Rightarrow {V_A} - {V_B} < 0\quad or,\quad {V_A} < {V_B}$

As ${V_A} < {V_B}$, so direction of current will be from $B$ to $A$.

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