MCQ
In the electrical circuit shown in the figure, the current $i$ through the side $AB$ is
- A$\frac{{10}}{{33}}A$
- B$\;\frac{1}{5}A$
- C$\;\frac{{10}}{{63}}A$
- ✓$\;\frac{6}{{25}}A$
✓
Answer
Correct option: D.
$\;\frac{6}{{25}}A$
d
$R_{eq}=25 \Omega$
$R_{eq}=25 \Omega$
$I=\frac{10}{25}$
$I=0.4$
$I_{(20\;\Omega)}=\frac{30 \times \frac{4}{10}}{20+30}=\frac{12}{50}=\frac{6}{25} A$
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