MCQ
In the electronic structure of $H_2SO_4$, the total number of unshared electrons is
- A$20$
- ✓$16$
- C$12$
- D$8$
bond.
In the molecule $\mathrm{H}_{2} \mathrm{SO}_{4}$
Electronic configuration of Oxygen is $1 s^{2} 2 s^{2} 2 p^{4}$
sulphur is $1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{6} 3 \mathrm{s}^{2} 3 \mathrm{p}^{4}$
hydrogen is $1 \mathrm{s}^{1}$
Total no. of outermost electrons $=6 \times 4+6 \times 1+1 \times 2=32$
no. of shared electrons $=2 \times$ no. of covalent bonds $=2 \times 8=16$
No. of unshared $\mathrm{e}^{-} \mathrm{s}=32-16=16$
Hence, the correct option is $\mathrm{B}$
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$I.$ Chlorobenzene
$II.$ Benzene
$III.$ Anilinium chloride
$IV.$ Toluene
