MCQ
The $pH$ of $ 0.1 \,M$ solution of a weak monoprotic acid $1\%$ ionized is
- A$1$
- B$2$
- ✓$3$
- D$4$
$ = 0.1 \times \frac{1}{{100}} = {10^{ - 3}}$; $({H^ + }) = {10^{ - 3}}$; $pH = 3$.
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