MCQ
In the experiment to determine the galvanometer resistance by half-deflection method, the plot of $\frac{1}{\theta}$ vs the resistance $(R)$ of the resistance box is shown in the figure. The figure of merit of the galvanometer is .............. $\times 10^{-1} \mathrm{~A} /$ division. [The source has emf 2V]
  • A
    $5$
  • B
    $6$
  • C
    $7$
  • D
    $8$

Answer

$i=K \theta$

$\frac{2}{G+R}=K \theta$

$\Rightarrow \frac{1}{\theta}=\frac{(G+R) K}{2}=R\left(\frac{K}{2}\right)+\frac{K G}{2}$

$\text { Slope }=\frac{K}{2}=\frac{1}{4} \Rightarrow K=0.5=5 \times 10^{-1} A$

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