MCQ
In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength ${\lambda _1}$ is found to be coincident with the third maximum at ${\lambda _2}$. So
- A$3{\lambda _1} = 0.3{\lambda _2}$
- B$3{\lambda _1} = {\lambda _2}$
- ✓${\lambda _1} = 3.5{\lambda _2}$
- D$0.3{\lambda _1} = 3{\lambda _2}$

