Question
In the figure, if $\angle ABC = 35^\circ$ then find $m(??? AXC ) ?$
✓
Answer
In the figure, arc $A X C$ is intercepted by $\angle A B C$.
$\therefore \angle ABC =\frac{1}{2} m ($ ar $AXC )$
...[[The measure of an inscribed angle is half of the measure of the arc intercepted by it]
$ \therefore m(\operatorname{arc} A X C)=2 \angle A B C$
$\therefore m(\operatorname{arc} A X C)=2 \times 35^{\circ}$
$\therefore m(\operatorname{arc} A X C)=70^{\circ} $
$\therefore m(\operatorname{arc} A X C)=2 \times 35^{\circ}$
$\therefore m(\operatorname{arc} A X C)=70^{\circ} $
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