Question
In the figure, if ∠ABC = 35°, then find m(arc AXC)?
✓
Answer
In the figure, arc $A X C$ is intercepted by $\angle A B C$.
$\therefore \angle ABC =\frac{1}{2} m ( ar AXC )$ ...[[The measure of an inscribed angle is half of the measure of the arc intercepted by it]
$\therefore m(\operatorname{arc} A X C)=2 \angle A B C$
$\therefore m (\operatorname{arc} AXC )=2 \times 35^{\circ}$
$\therefore m (\operatorname{arc} AXC )=70^{\circ}$
$\therefore \angle ABC =\frac{1}{2} m ( ar AXC )$ ...[[The measure of an inscribed angle is half of the measure of the arc intercepted by it]
$\therefore m(\operatorname{arc} A X C)=2 \angle A B C$
$\therefore m (\operatorname{arc} AXC )=2 \times 35^{\circ}$
$\therefore m (\operatorname{arc} AXC )=70^{\circ}$
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