MCQ
In the figure, if $\angle\text{AOB}=125^\circ$ then $\angle\text{COD}$ is equal to :
- A$45^\circ$
- B$35^\circ$
- ✓$55^\circ$
- D$62\frac{1}{2}^\circ$
✓
Answer
Correct option: C.
$55^\circ$
We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle
$\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\angle\text{COD}=180^\circ-\angle\text{AOB}$
$=180^\circ-125^\circ=55^\circ$
$\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\angle\text{COD}=180^\circ-\angle\text{AOB}$
$=180^\circ-125^\circ=55^\circ$
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