MCQ
In the figure, if $\ce{\angle DAB=60^{\circ}, \angle ABD}=50^{\circ}$, then $\ce{\angle ACB}$ is equal to :
- A$80^{\circ}$
- B$60^{\circ}$
- C$50^{\circ}$
- ✓$70^{\circ}$
✓
Answer
Correct option: D.
$70^{\circ}$
In, $\ce{\triangle ABD}$
$\angle D=180^{\circ}-\angle A-\angle B$
$=180^{\circ}-110^{\circ}$
$=70^{\circ}$
Since angles made by same chord at any point of circumference are equal.
so, $\ce{\angle ACB=\angle ADB}=70^{\circ}$
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