In the figure shown, the total resistance between $A$ and $B$ is ............. $\Omega$
Medium
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The last two resistance are out of circuit.
Now $8\,\Omega $ is in parallel with $(1 + 1 + 4 + 1 + 1)\,\Omega $.
$\therefore R = 8\,\Omega ||8\,\Omega = \frac{8}{2} = 4\,\Omega $ $ \Rightarrow $ ${R_{AB}} = 4 + 2 + 2 = 8\,\Omega $
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