In the figure, the perimeter of $\triangle\text{ABC}$ is :
✓
$30\ cm$
B
$60\ cm$
C
$45\ cm$
D
$15\ cm$
✓
Answer
Correct option: A.
$30\ cm$
By the property of tangent
$AO = AR = 4\ cm\ ($tangent from $A)$
$BR = BP = 6\ cm\ ($tangent from $B)$
$PC = CQ = 5\ cm\ ($tangent from $C)$
Perimeter of $\triangle\text{ABC} = AB + BC + CA$
Perimeter of $\triangle\text{ABC} = AR + BR + BP + PC + CQ + QA$
Perimeter of $\triangle\text{ABC} = 4 + 6 + 6 + 5 + 5 + 4$
Perimeter of $\triangle\text{ABC} = 30\ cm$
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