b
Potential gradient $(\mathrm{x})=\frac{\mathrm{IR}}{\mathrm{L}}$
$\quad=\frac{\varepsilon}{10 \mathrm{r}} \frac{9 \mathrm{r}}{\mathrm{L}}$
$=\frac{9 \varepsilon}{10 L}$
$\because \frac{\varepsilon}{2}=\mathrm{x} \times \ell_{\mathrm{AJ}}$
$C_{\mathrm{AJ}}=\frac{\varepsilon}{2} \times \frac{10 \mathrm{L}}{9 \varepsilon}=\frac{5 \mathrm{L}}{9}$