Question
In the following case state whether the function is bijective or not. Justify your answer
$f: R \rightarrow R$ defined by $f(x)=3-4 x^2$

Answer

$f(x)=3-4 x^2$
$f(1)=3-4(1)^2=3-4=-1$
$f(2)=3-4(2)^2=3-16=-13$
$f(3)=3-4(3)^2=3-36=-33$
$f(4)=3-4\left(4^2\right)=3-64=-61$
It is not a bijective function.
The positive numbers " $R$ " does not have a negative pre-image in $X$ in $R$.

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