d
(d) In steady state current flows through $4\, \Omega$ resistance only and it is $i = \frac{{10}}{{(4 + 1)}} = 2\,amp$.
Potential difference across $4\, \Omega$ resistance is $V = 2 \times 4 = 8\,volt$
Hence, potential difference across each capacitor is $4\,V$
So charge on each capacitor $Q = 3 \times 4 = 12 \,\mu C$.