MCQ
In the given circuit calculate potential difference between $A$ and $B$ ............... $\mathrm{V}$
- A$-5.8$
- B$-4.6$
- C$-5.8$
- ✓$-5.2$
✓
Answer
Correct option: D.
$-5.2$
d
$\mathrm{K.V}$ $\mathrm{.L.}$ on left mesh
$\mathrm{K.V}$ $\mathrm{.L.}$ on left mesh
${2-3 \mathrm{I}_{1}-2 \mathrm{I}_{1}=0} $
${\mathrm{I}_{1}=0.4 \mathrm{\,amp}}$
$\mathrm{K.V.L.}$ on right mesh
$4-3 I_{2}-5 I_{2}=0$
$\mathrm{I}_{2}=0.5 \mathrm{\,amp}$
Potential difference between $A $ and $ B$
${\mathrm{V}_{\mathrm{A}}+3 \mathrm{I}_{1}+4=\mathrm{V}_{\mathrm{B}}} $
${\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-3(\mathrm{O} .4)-4=-5.2 \mathrm{\,V}}$
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