In the given circuit diagram the current through the battery and the charge on the capacitor respectively in steady state are
Medium
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At steady state no current flows through capacitor branch.
$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{eq}}}\left[\frac{1}{\mathrm{R}_{\mathrm{eq}}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}\right]\left[\frac{1}{\mathrm{R}_{\mathrm{eq}}}=\frac{11}{6}\right]$
$I=6 \times \frac{11}{6}=11 \,A$
$\mathrm{Q}=\mathrm{CV}=0.5 \times 6=3\, \mu \mathrm{C}$
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