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In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance $C$ will be
  • A$CE$
  • B$CE$$\;\frac{{\;{r_1}}}{{\left( {{r_2} + r} \right)}}$
  • C$CE$$\;\frac{{\;{r_2}}}{{\left( {r + {r_2}} \right)}}$
  • D$CE$$\;\frac{{\;{r_1}}}{{\left( {{r_1} + r} \right)}}$
JEE MAIN 2017, Medium
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