MCQ
In the given circuit The current through the battery is........$A$
- A$0.5$
- B$1$
- ✓$1.5$
- D$2$
✓
Answer
Correct option: C.
$1.5$
c
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The negative of the work done by the conservative internal forces on a system equals the change in:
Two bulbs of 500 watt and 200 watt are manufactured to operate on 220 volt line. The ratio of heat produced in 500 W and 200 W, in two cases, when firstly they are joined in parallel and secondly in series, will be
The graph in figure shows how the count-rate $A$ of a radioactive source as measured by a Geiger counter varies with time $t.$ The relationship between $A$ and $t$ is : $($ Assume $ln\,\, 12 = 2.6)$
→Every atom makes one free electron in copper. If $1.1$ $ampere$ current is flowing in the wire of copper having $1\, mm$ diameter, then the drift velocity (approx.) will be (Density of copper $ = 9 \times {10^3}\,kg\,{m^{ - 3}}$ and atomic weight = $63$)
→Beta rays emitted by a radioactive material are
Given below are two statements; one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
→Assertion $A:$ Electromagnets are made of soft iron.
Reason $R:$ Soft iron has high permeability and low retentivity.
In the light of above, statements, choose the most appropriate answer from the options given below.
Out of the following which one is a forward biased diode?
Charges $Q, 2Q$ and $4Q$ are uniformly distributed in three dielectric solid spheres $1,2$ and $3$ of radii $R/2, R$ and $2 R$ respectively, as shown in figure. If magnitudes of the electric fields at point $P$ at a distance $R$ from the centre of spheres $1,2$ and $3$ are $E_1 E_2$ and $E_3$ respectively, then
→Van de Graaff generator is used to:
Let $\text{E}_\text{n}=\frac{-1}{8\in_0^2}\frac{\text{me}^4}{\text{n}^2\text{h}^2}$ be the energy of the nth level of H-atom. If all the H-atoms are in the ground state and radiation of frequency $\frac{(\text{E}_2-\text{E}_1)}{\text{h}}$ falls on it:
→