In the given figure, AB is the diameter of the circle with centre O.
If ∠ADC = 32°, find angle BOC
If ∠ADC = 32°, find angle BOC
Exercise 17 (C) | Q 12 | Page 266
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Arc AC subtends ∠AOC at the centre and ∠ADC at the remaining part Of the circle
∴ ∠AOC = 2 ∠ADC
⇒∠AOC = 2× 32° = 64°
Since ∠AOC and ∠BOC are linear pair, we have
∠AOC + ∠BOC = 180°
⇒ 64° + BOC = 180°
⇒ ∠BOC = 180°
⇒ ∠BOC = 180° - 64°
⇒∠BOC = 116°
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