MCQ
- A55º
- B75º
- C65º
- D45º
✓
Answer
- 55º
Solution:
$\angle\text{BAF}=\angle\text{DCF}=80^\circ$ (Corresponding angle)
In $\triangle\text{CEF}$
$\angle\text{CFE}+\angle\text{CEF}=\angle\text{DCF}$ (exterior angle is equal to the sum of its two opposite interior angles)
$25^\circ+\angle\text{CEF}=80^\circ$
$\angle\text{CEF}=55^\circ$
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