Question
In the given figure, $\angle\text{ABD}=54^\circ$ and $\angle\text{BCD}=43^\circ,$ calculate
$i. \angle\text{ACD}$
$ii. \angle\text{BAD}$
$iii. \angle\text{BDA}$

Answer


$i.$ We know that the angles in the same segment of a circle are equal.
$\text{i.e.},\angle\text{ABD}=\angle\text{ACD}=54^\circ$
$ii.$ We know that the angles in the same segment of a circle are equal.
$\text{i.e.},\angle\text{BAD}=\angle\text{BCD}=43^\circ$
$iii.$ In $\triangle\text{ABD},$ we have:
$\angle\text{BAD}+\angle\text{ADB}+\angle\text{DBA}=180^\circ [$Angle sum property of a triangle$]$
$\Rightarrow\ 43^\circ+\angle\text{ADB}+54^\circ=180^\circ$
$\Rightarrow\ \angle\text{ADB}=(180^\circ-97^\circ)=83^\circ$
$\Rightarrow\ \angle\text{BDA}=83^\circ$

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