MCQ
In the given figure force on wire $ABC$ will be $(B = 2T)$


- A$4(3+2\pi ) N$
- ✓$20\,N$
- C$10\,N$
- D$40\,N$

Force on $\mathrm{BC}=16 \mathrm{\,N}$ (left)
so force on $\mathrm{ABC}=\sqrt{(12)^{2}+(16)^{2}}=20 \mathrm{\,N}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$1.$ The magnitude of the induced electric field in the orbit at any instant of time during the time interval of the magnetic field change is :
$(A)$ $\frac{B R}{4}$ $(B)$ $\frac{B R}{2}$ $(C)$ $BR$ $(D)$ $2BR$
$2.$ The change in the magnetic dipole moment associated with the orbit, at the end of the time interval of the magnetic field change, is:
$(A)$ $-\gamma B Q R^2$ $(B)$ $-\gamma \frac{B Q R^2}{2}$ $(C)$ $\gamma \frac{ BQR ^2}{2}$ $(D)$ $\gamma B Q R^2$
Give the answer question $1$ and $2.$