In the given figure initially the capacitor is uncharged. Ratio of current at $t = 0$ & $t = \infty$ will be
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at $t=0 \quad$ at $t=\infty$
$\mathrm{I}_{\mathrm{t}=0}=\mathrm{E} / \mathrm{R} \quad \mathrm{I}_{\mathrm{t}=\infty}=\mathrm{E} / 2 \mathrm{R}$
$\frac{I_{t=0}}{I_{t=\infty}}=\frac{E / R}{E / 2 R}=2$
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