Answer

  1. 115º
    Solution:
    $\angle\text{AOC}+\angle\text{BOD}=1306^\circ$ (given)
    But $\angle\text{AOC}=\angle\text{BOD}$ (Vartically Opposite angles)
    $\Rightarrow2\angle\text{AOC}=130^\circ$
    $\Rightarrow\angle\text{AOC}=65^\circ$
    Since COD is a straight line,
    $\angle\text{AOC}+\angle\text{AOD}=180^\circ$
    $\Rightarrow65^\circ+\angle\text{AOD}=180^\circ$
    $\Rightarrow\angle\text{AOD}=115^\circ$

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