In the given figure, the centre O of the small circle lies on the circumference of the bigger circle. If ∠APB = 75° and ∠BCD = 40°, find : ∠AOB
Exercise 17 (A) | Q 53.1 | Page 262
Download our app for free and get started
Join AB and AD
∠AOB = 2 ∠APB = 2 ×75° =150°
(Angle at the centre is double the angle at the circumference subtended by the same chord).
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionIn the figure, given alongside, AB ∥ CD and O is the centre of the circle. If ∠ADC = 25°; find
the angle AEB give reasons in support of your answer.
- 2In the given figure, $A O B$ is a diameter and $D C$ is parallel to $A B$. If $\angle C A B=x^0$; find (in terms of $x$ ) the values of: $\angle$ ADC.View Solution
- 3View SolutionIn the given figure, AC is a diameter of circle, centre O. Chord BD is perpendicular to AC. Write down the angles p, q and r in terms of x .
- 4View SolutionProve that:
the parallelogram, inscribed in a circle, is a rectangle. - 5In the given figure, AC is the diameter of circle, centre $\mathrm{O} . \mathrm{CD}$ and BE are parallel. Angle $\mathrm{AOB}=80^{\circ}$ and angle $\mathrm{ACE}=$ $10^{\circ}$. Calculate : Angle BCDView Solution
- 6View SolutionIn the given figure, O is the centre of the circle. ∠OABand ∠OCB are 30° and 40°
respectively. Find ∠AOC . Show your steps of working.
- 7View SolutionIn the given figure, RS is a diameter of the circle. NM is parallel to RS and ∠MRS = 29°.
Calculate : ∠ NRM
- 8View SolutionIn the given figure, ∠BAD = 65°, ∠ABD = 70° and ∠BDC = 45°. Find: ∠ ACB.
Hence, show that AC is a diameter.
- 9View SolutionIn the figure, given below, ABCD is a cyclic quadrilateral in which ∠BAD = 75°; ∠ABD = 58°
and ∠ADC = 77°. Find:
1. ∠BDC
2. ∠BCD
3. ∠BCA.
- 10View SolutionIn the given figure, AOC is a diameter and AC is parallel to ED. If ∠CBE = 64°, Calculate ∠DEC .
