Prove that: the parallelogram, inscribed in a circle, is a rectangle.
Exercise 17 (A) | Q 20.1 | Page 259
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Let ABCD be a parallelogram, inscribe in a circle, Now, ∠BAD = ∠BCD (Opposite angles of a parallelogram are equal) And ∠BAD = ∠BCD = 180° (pair of opposite angles in a cyclic quadrilateral are supplementary) $\angle BAD =\angle BCD =\frac{180^{\circ}}{2}=90^{\circ}$ ∥y, the other two angles are 90 and opposite pair of sides Are equal. ∴ ABCD is a rectangle.
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In the given figure, AB is a diameter of the circle with centre O. DO is parallel to CB and ∠DCB = 120°.
Calculate : ∠DAB
Also show that the ΔAOD is an equilateral triangle .
In the given figure, M is the centre of the circle. Chords AB and CD are perpendicular to each other. If ∠MAD = x and ∠BAC = y : express ∠AMD in terms of x.