Question
In the given figure, the current amplitude is
✓
Answer
$V_{e q}=\sqrt{V_{0}^{2}+\left(\frac{V_{0}}{2}\right)^{2}}$
$\mathrm{R}_{\mathrm{eq}}=\sqrt{(\omega \mathrm{L})^{2}+\mathrm{R}^{2}}$
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