In the given figure, the directed lines are parallel to each othe… - Vidyadip

Question

In the given figure, the directed lines are parallel to each other. Find the unknown angles.

✓

Answer

∵ Lines are parallel
∴ x = p
and p + 120° = 180° ........(alternate angles)
⇒ p = 180°− 120° = 60°
∴ x = 60°
q = 120° ........(corresponding angles)
y = 110° .........(vertically opposite angles)
and ∠1 + 110° = 180° .......(co-interior angles)
∴ ∠1 = 180°− 110° = 70°
But z = ∠1 .........(vertically opposite angles)
∴ ∠z = 70°
Hence x = 60°, y = 110°, z = 70°, p = 60°. q = 120°

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "[4 marks sum]" from Lines and Angles (Including Construction of angles)→Lines and Angles (Including Construction of angles) — all question types→MATHS STD 7 question papers→ICSE Board STD 7 question papers→ICSE Board question paper generator→

Similar questions

Kapil is an expert cyclist. Every morning he starts from his home on his cycle and rides on the road running parallel to the railway track, to reach the railway crossing, 27 km away from his home.
Q.1. Today he managed to reach the railway crossing in 3 hours. Find his speed in m/sec:
(a) 2 m/sec$\quad$$\quad$ (b) 2.5 m/sec $\quad$$\quad$(c) 3 m/sec $\quad$$\quad$(d) 4.5 m/sec
Q.2. If tomorrow he wishes to cover this distance in 2 hours, by how much does he need to increase his speed?
(a) 1.25 m/s$\quad$$\quad$ $\quad$$\quad$(b) 1.5 m/s$\quad$$\quad$ (c) 1.75 m/s $\quad$$\quad$(d) 2.25 m/s
Q.3. Today, he has to stop at the railway crossing for a train to pass. What time will the train 180 m long, running at 54 km per hour take to pass him:
(a) 9 sec$\quad$$\quad$(b) 10 sec $\quad$$\quad$(c) 12 sec $\quad$$\quad$(d) 15 sec
Q.4. What time will this train take to pass a platform 300 m long at the speed of 10 m/s?
(a) 30 sec $\quad$$\quad$(b) 32 sec $\quad$$\quad$(c) 36 sec$\quad$$\quad$ (d) 35 sec

Evaluate: $\left(\frac{11}{-9} \times \frac{21}{44}\right)+\left(\frac{-5}{9}\right) \times\left(\frac{63}{-100}\right)$

Evaluate: $\left(\frac{-4}{5} \times \frac{3}{2}\right)+\left(\frac{9}{-5} \times \frac{10}{3}\right)-\left(\frac{-3}{2} \times \frac{-1}{4}\right)$

State Pythagoras' Theorem.

Find the S.I. and amount on: 600 from July 12 to Dec. 5 at 10% p.a.

The length and breadth of a rectangular piece of land are in the ratio $5 : 3$. If the total cost of fencing it at the rate of $₹\ 24$ per meter is $₹\ 9600$, find its $:$
$(i)$ length and breadth
$(ii)$ area
$(iii)$ cost of levelling at the rate of $₹\ 60$ per $m^2$.

The sum of three consecutive odd numbers is 63. Find the numbers.

Evaluate: $\frac{9}{-16}+\left(-\frac{5}{-12}\right)$

Oranges are bought at 100 for ?80 and all of them are sold at ₹80 for ₹100. Find the loss or gain as percent in this transaction.

Evaluate: $\frac{-11}{12}+\frac{5}{16}+\frac{-3}{8}$