We know that tangent from an external point to a circle are equal.
So,
$AF = AE = 4\ cm$
$\Rightarrow EC = AC - AE $
$= 11 - 4 = 7\ cm$
Now,
$CD = CE = 7\ cm$
and $BF = BD = 3\ cm$
$BD = BD + CD$
$\Rightarrow BD = 3 + 7$
$\Rightarrow BD = 10\ cm$
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