In the given potentiometer circuit arrangement, the balancing length ${AC}$ is measured to be $250$ ${cm}$. When the galvanometer connection is shifted from point $(1)$ to point $(2)$ in the given diagram, the balancing length becomes $400\, {cm}$. The ratio of the emf of two cells, $\frac{\varepsilon_{1}}{\varepsilon_{2}}$ is -
  • A$\frac{4}{3}$
  • B$\frac{3}{2}$
  • C$\frac{5}{3}$
  • D$\frac{8}{5}$
JEE MAIN 2021, Diffcult
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