In the ladder network shown, current through the resistor $3\, \Omega$ is $0.25\,A$. The input voltage $'V'$ is equal to:- ........... $V$
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$\mathrm{R}_{\mathrm{eq}}=7+4+9=20\, \Omega$
$\mathrm{V}=\mathrm{IR}_{\mathrm{eq}}=1 \times 20=20 \mathrm{\,V}$
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