MCQ
In the mixture of conc. ${H_2}S{O_4}$ and $HN{O_3}$the nitrating species is
- A${N_2}{O_4}$
- ✓$NO_2^ + $
- C$N{O_2}$
- D$NO_2^ - $
$HONO _2+2 H _2 SO _4 \rightleftarrows H _3 O ^{+}+2 HSO _4^{-}+\underset{\text { (nitronium ion) }}{ NO _2^{+}}$
So nitrating species is $NO _2^{+}$ ion.
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$N{H_4}^ + + {S^{ - 2}} \rightleftharpoons N{H_3} + H{S^ - }$
$\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^1}} \right);\,\,R\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^2}} \right)$The formula of ionic compounds that can be formed between these elements are
$X + C{r_2}{O_3}\xrightarrow{\Delta }Y$ (Green coloured)
$X$ and $Y$ are