In the parabola y^2 = 6x, the equation of the chord through verte… - Vidyadip

MCQ

In the parabola ${y^2} = 6x$, the equation of the chord through vertex and negative end of latus rectum, is

A
$y = 2x$
✓
$y + 2x = 0$
C
$x = 2y$
D
$x + 2y = 0$

✓

Answer

Correct option: B.

$y + 2x = 0$

b
(b) Vertex $ \equiv (0,0),$ End points of latus rectum are $(a,\,\, \pm \,\,2a)$.

Here $a = \frac{6}{4}$

Therefore, $ - ve$end of latus rectum is $\left( {\frac{3}{2},\, - 3} \right)$

Line through the point is $y = \frac{{ - 3}}{{3/2}}x$or $y + 2x = 0$.

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