In the reaction at 300 , K C_6 H_6 ( ) + 15 2 O_2 6C O_2 ( g ) + 3 H_2 O ( ) , , , , H = - 3271 ,kJ What is the value of U for combustion of 1.5 , mol benzene at 27 ,^oC ? .....kJ

In the reaction at 300 , K C_6 H_6 ( ) + 15 2 O_2 6C O_2 ( g ) + …

MCQ

In the reaction at $300\, K$

${C_6}{H_6}\left( \ell \right) + \frac{{15}}{2}{O_2} \to 6C{O_2}\left( g \right) + 3{H_2}O\left( \ell \right)\,\,\,\,\Delta H = - 3271\,kJ$

What is the value of $\Delta U$ for combustion of $1.5\, mol$ benzene at $27\,^oC$ ? .....$kJ$

✓

Correct option: B.

$-4900.88$

b
for $1$ $mol$ combustion of benzene

$\Delta \mathrm{n}_{\mathrm{g}}=-1.5$

$\Delta \mathrm{H}=\Delta \mathrm{U}+\Delta \mathrm{ngRT}$

$\Rightarrow-3271=\Delta \mathrm{U}-\frac{1.5 \times 8.314 \times 300}{1000}$

$\Rightarrow \Delta \mathrm{U}=-3267.25\, \mathrm{kJ}$

for $1.5 \,\mathrm{mol}$

$\Delta \mathrm{U}=-3267.25 \times 1.5=-4900.88\, \mathrm{kJ}$

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