MCQ
In the reaction $C{H_3}CH = C{H_2} + {H_2}O + \mathop {[O]}\limits_{Acid} $ $ \xrightarrow[Acid]{KMnO_4} $ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,\,OH}
\end{array}$ $\xrightarrow{{[O]}}X + HCOOH$
{C{H_3} - CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,\,OH}
\end{array}$ $\xrightarrow{{[O]}}X + HCOOH$
$X$ is
- A$C{H_3}C{H_2}COOH$
- ✓$C{H_3}COOH$
- C$C{H_3}C{H_2}CHO$
- D$C{H_3}C{H_2}OH$