MCQ
In the relation $n = \frac{{PV}}{{RT}},n = $
  • A
    Number of molecules
  • B
    Atomic number
  • C
    Mass number
  • Number of moles

Answer

Correct option: D.
Number of moles
d
$n=\frac{P V}{R T}$

Writing the units of all the terms of Right Hand Side, in $SI$ units

$n=\frac{(P a) \times\left(m^{3}\right)}{(J / mol / k) \cdot(k)}$

$n=\frac{\left(\frac{N}{m^{2}}\right) \cdot\left(m^{3}\right)}{\left(\frac{J}{\text { mol. K }}\right) \cdot(k .)}$

$n=\frac{\frac{ kgm }{ s ^{2} \cdot m ^{2}} \cdot m ^{3}}{\frac{ kg m ^{2}}{ s ^{2} \cdot mol \cdot K } \cdot K .}$

$n=\operatorname{mol}$. [All other terms cancel out]

Correct choice - option - $D$

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