Two capacitors of capacitance $2C$ and $C$ are joined in parallel and charged to potential $V$. The battery is now removed and the capacitor $C$ is filled with a medium of dielectric constant $K$. The potential difference across each capacitor will be
A$\frac{{3V}}{{K + 2}}$
B$\frac{{3V}}{K}$
C$\frac{V}{{K + 2}}$
D$\frac{V}{K}$
Medium
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A$\frac{{3V}}{{K + 2}}$
a $\mathrm{Q}_{\text {total }}=\mathrm{CV}+2 \mathrm{CV}=3 \mathrm{CV}$
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