MCQ
In the shown $AC$ circuit phase different between currents $I_1$ and $I_2$ is


- A$\frac{\pi }{2} - {\tan ^{ - 1}}\,\frac{{{x_L}}}{R}$
- B${\tan ^{ - 1}}\,\frac{{{x_L} - {x_C}}}{R}$
- ✓$\frac{\pi }{2} + {\tan ^{ - 1}}\,\frac{{{x_L}}}{R}$
- D${\tan ^{ - 1}}\,\frac{{{x_L} - {x_C}}}{R} + \frac{\pi }{2}$
