In the Young's double slit experiment, if the phase difference be… - Vidyadip

MCQ

In the Young's double slit experiment, if the phase difference between the two waves interfering at a point is $\phi$, the intensity at that point can be expressed by the expression

A
$I = \sqrt {{A^2} + {B^2}{{\cos }^2}\phi } $
B
$I = \frac{A}{B}\cos \phi $
C
$I = A + B\cos \frac{\phi }{2}$
✓
$I = A + B\cos \phi $Where $A $ and $B $ depend upon the amplitudes of the two waves.

✓

Answer

Correct option: D.

$I = A + B\cos \phi $Where $A $ and $B $ depend upon the amplitudes of the two waves.

d
(d)$I = a_1^2 + a_2^2 + 2{a_1}{a_2}\cos \phi $
Put $a_1^2 + a_2^2 = A$and ${a_1}{a_2} = B;\;\;\therefore I = A + B\cos \phi $

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