MCQ
In the Young's double slit experiment, if the phase difference between the two waves interfering at a point is $\phi$, the intensity at that point can be expressed by the expressionWhere $A$ and $B$ depend upon the amplitudes of the two waves.
  • A
    (a) $I=\sqrt{A^2+B^2 \cos ^2 \phi}$
  • B
    (b) $I=\frac{A}{B} \cos \phi$
  • C
    (c) $I=A+B \cos \frac{\phi}{2}$
  • (d) $I=A+B \cos \phi$

Answer

Correct option: D.
(d) $I=A+B \cos \phi$
(d) Since $P$ is ahead of $Q$ by 90 and path difference between $P$ and $Q$ is $\lambda / 4$. Therefore at $A$, phase difference is zero, so intensity is 4l. At $C$ it is zero and at $B$, the phase difference is 90 , so intensity is $2 l$.

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