MCQ
In thiosulphuric acid
- Aeach sulphar atom is in identical oxidation state
- ✓there is a $S = S$ linkage present
- Cone $S$ atom is in $+2$ and other sulpher atom is in $+4$ oxidation state
- Dthere is only one replaceabe hydrogen atom

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| $Pb ^{2+} / Pb$ | $-0.13 V$ |
| $Ni ^{2+} / Ni$ | $-0.24 V$ |
| $Cd ^{2+} / Cd$ | $-0.40 V$ |
| $Fe ^{2+} / Fe$ | $V-0.44 V$ |
To a solution containing $0.001 M$ of $X ^{2+}$ and $0.1 M$ of $Y ^{2+}$, the metal rods $X$ and $Y$ are inserted (at $298 K$ ) and connected by a conducting wire. This resulted in dissolution of $X$. The correct combination(s) of $X$ and $Y$, respectively, is (are)
(Given: Gas constant, $R =8.314 J K ^{-1} mol ^{-1}$,
Faraday constant, $F =96500 C mol ^{-1}$ )
$(A)$ $Cd$ and $Ni$ $(B)$ $Cd$ and $Fe$ $(C)$ $Ni$ and $Pb$ $(D)$ $Ni$ and $Fe$


$(a)$ The vapour pressure of water at $280 K$ is $14.2$ $mm Hg$
$(b)$ $R =0.082 L$ atm $K ^{-1} mol ^{-1}$