Question
In trapezium $ABCD$ with $AB || CD,$ if $\angle\text{A}=100^\circ, \text{then}\ \angle\text{D}=$ _____.
✓
Answer
In trapezium $ABCD$ with $AB || CD,$
if $\angle\text{A}=100^\circ, \text{then}\ \angle\text{D}= 80^\circ .$
Solution: In trapezium, we know that, the angles on either sides of the base are supplementary.
So, in trapezium $ABCD,$ given $?? || ??$
$\therefore\angle\text{A}+\angle\text{D}=180^\circ$
$\Rightarrow100^\circ+\angle\text{D}\ 180^\circ$
$\Rightarrow\angle\text{D}=180^\circ-100^\circ$
$\Rightarrow\angle\text{D}=80^\circ$
if $\angle\text{A}=100^\circ, \text{then}\ \angle\text{D}= 80^\circ .$
Solution: In trapezium, we know that, the angles on either sides of the base are supplementary.
So, in trapezium $ABCD,$ given $?? || ??$
$\therefore\angle\text{A}+\angle\text{D}=180^\circ$
$\Rightarrow100^\circ+\angle\text{D}\ 180^\circ$
$\Rightarrow\angle\text{D}=180^\circ-100^\circ$
$\Rightarrow\angle\text{D}=80^\circ$
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