MCQ
In $\triangle A B C$ and $\triangle D E F$ its is given that $\angle B=\angle E$ and $\angle C=\angle F$ in order that $\triangle A B C \cong \triangle D E F$ we must have
- A$BC = EF$
- B$\angle A=\angle D$
- C$A B=D F$
- D$AC = DE$
✓
Answer
(a) $BC = EF$
Explanation: In $\triangle A B C$ and $\triangle D E F$
$\angle B=\angle E$ and $\angle C=\angle F$
For congruence, $BC = EF$
Therefore by AAS axiom
$\triangle A B C \cong \triangle D E F$
Explanation: In $\triangle A B C$ and $\triangle D E F$
$\angle B=\angle E$ and $\angle C=\angle F$
For congruence, $BC = EF$
Therefore by AAS axiom
$\triangle A B C \cong \triangle D E F$
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