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Introduction of Trigonometry — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsIntroduction of Trigonometry1 Mark
MCQ
In $\triangle A B C, \angle B=90^{\circ}, \angle A=30^{\circ}$ and $A B=9 cm$.Then, $B C=$
Image
  • A
    $3 cm$
  • B
    $2 \sqrt{8} cm$
  • ✓
    $3 \sqrt{3} cm$
  • D
    $6 cm$
✓

Answer

Correct option: C.
$3 \sqrt{3} cm$
(c) $=$ We have, $^{\tan 30^{\circ}}=\frac{B C}{A B}=\frac{1}{\sqrt{3}}$
$\Rightarrow \frac{B C}{9}=\frac{1}{\sqrt{3}}$
[Given, $A B=9 cm$ ]
$\Rightarrow B C=\left(9 \times \frac{1}{\sqrt{3}}\right) cm =3 \sqrt{3} cm$

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