MCQ
In triangle $ABC , a =2, b-3$ and $\sin$ $A=\frac{2}{3}$, then B is equal to
  • A
    $30^{\circ}$
  • B
    $60^{\circ}$
  • $90^{\circ}$
  • D
    $120^{\circ}$

Answer

Correct option: C.
$90^{\circ}$
(C) By sine rule,
$\frac{\sin A}{a}=\frac{\sin B}{b}$
$\begin{array}{l}\Rightarrow \frac{2 / 3}{2}=\frac{\sin B}{3} \\ \Rightarrow \sin B=1=\sin 90^{\circ} \Rightarrow B=90^{\circ}\end{array}$

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