MCQ
In $\triangle ABC , \angle B =90^{\circ}, AB =5 cm$ and $BC =12 cm$. Then $\sin C =$
- A$\frac{12}{13}$
- ✓$\frac{5}{13}$
- C$\frac{5}{12}$
- D$\frac{13}{5}$
In $\triangle ABC , \angle B =90^{\circ}, AB =5 cm$ and $BC =12 cm$. Then $\sin C =$
✓
Answer
Correct option: B.
$\frac{5}{13}$
B
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